10111310140131 has 64 divisors (see below), whose sum is σ = 15528503007360. Its totient is φ = 6498071838720.

The previous prime is 10111310140093. The next prime is 10111310140189. The reversal of 10111310140131 is 13104101311101.

10111310140131 is a `hidden beast` number, since 101 + 1 + 131 + 0 + 1 + 401 + 31 = 666.

It is not a de Polignac number, because 10111310140131 - 2¹³ = 10111310131939 is a prime.

It is a super-2 number, since 2×10111310140131² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10111310140031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 66176535 + ... + 66329151.

It is an arithmetic number, because the mean of its divisors is an integer number (242632859490).

Almost surely, 2^{10111310140131} is an apocalyptic number.

10111310140131 is a deficient number, since it is larger than the sum of its proper divisors (5417192867229).

10111310140131 is a wasteful number, since it uses less digits than its factorization.

10111310140131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153381 (or 153375 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 10111310140131 its reverse (13104101311101), we get a palindrome (23215411451232).

The spelling of 10111310140131 in words is "ten trillion, one hundred eleven billion, three hundred ten million, one hundred forty thousand, one hundred thirty-one".