1011131101401 has 4 divisors (see below), whose sum is σ = 1348174801872. Its totient is φ = 674087400932.

The previous prime is 1011131101397. The next prime is 1011131101417. The reversal of 1011131101401 is 1041011311101.

1011131101401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011131101401 - 2² = 1011131101397 is a prime.

It is a super-2 number, since 2×1011131101401² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1011131101451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168521850231 + ... + 168521850236.

It is an arithmetic number, because the mean of its divisors is an integer number (337043700468).

Almost surely, 2^{1011131101401} is an apocalyptic number.

It is an amenable number.

1011131101401 is a deficient number, since it is larger than the sum of its proper divisors (337043700471).

1011131101401 is an equidigital number, since it uses as much as digits as its factorization.

1011131101401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337043700470.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 1011131101401 its reverse (1041011311101), we get a palindrome (2052142412502).

The spelling of 1011131101401 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred one thousand, four hundred one".