1011131101451 has 2 divisors, whose sum is σ = 1011131101452. Its totient is φ = 1011131101450.

The previous prime is 1011131101417. The next prime is 1011131101457. The reversal of 1011131101451 is 1541011311101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011131101451 is a prime.

It is a super-2 number, since 2×1011131101451² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011131101457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565550725 + 505565550726.

It is an arithmetic number, because the mean of its divisors is an integer number (505565550726).

Almost surely, 2^{1011131101451} is an apocalyptic number.

1011131101451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011131101451 is an equidigital number, since it uses as much as digits as its factorization.

1011131101451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 20.

Adding to 1011131101451 its reverse (1541011311101), we get a palindrome (2552142412552).

The spelling of 1011131101451 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred one thousand, four hundred fifty-one".