1011131101417 has 2 divisors, whose sum is σ = 1011131101418. Its totient is φ = 1011131101416.

The previous prime is 1011131101397. The next prime is 1011131101451. The reversal of 1011131101417 is 7141011311101.

It is a happy number.

1011131101417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 676282548496 + 334848552921 = 822364^2 + 578661^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011131101417 - 2¹⁹ = 1011130577129 is a prime.

It is a super-2 number, since 2×1011131101417² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011131101457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565550708 + 505565550709.

It is an arithmetic number, because the mean of its divisors is an integer number (505565550709).

Almost surely, 2^{1011131101417} is an apocalyptic number.

It is an amenable number.

1011131101417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011131101417 is an equidigital number, since it uses as much as digits as its factorization.

1011131101417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 22.

Adding to 1011131101417 its reverse (7141011311101), we get a palindrome (8152142412518).

The spelling of 1011131101417 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred one thousand, four hundred seventeen".