101113112330 has 8 divisors (see below), whose sum is σ = 182003602212. Its totient is φ = 40445244928.

The previous prime is 101113112297. The next prime is 101113112449. The reversal of 101113112330 is 33211311101.

It can be written as a sum of positive squares in 2 ways, for example, as 84200369929 + 16912742401 = 290173^2 + 130049^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×101113112330² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101113112299 and 101113112308.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5055655607 + ... + 5055655626.

Almost surely, 2^101113112330 is an apocalyptic number.

101113112330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101113112330 is a deficient number, since it is larger than the sum of its proper divisors (80890489882).

101113112330 is a wasteful number, since it uses less digits than its factorization.

101113112330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10111311240.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101113112330 its reverse (33211311101), we get a palindrome (134324423431).

The spelling of 101113112330 in words is "one hundred one billion, one hundred thirteen million, one hundred twelve thousand, three hundred thirty".