1011131323 has 2 divisors, whose sum is σ = 1011131324. Its totient is φ = 1011131322.

The previous prime is 1011131311. The next prime is 1011131333. The reversal of 1011131323 is 3231311101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011131323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011131297 and 1011131306.

It is not a weakly prime, because it can be changed into another prime (1011131333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565661 + 505565662.

It is an arithmetic number, because the mean of its divisors is an integer number (505565662).

Almost surely, 2^1011131323 is an apocalyptic number.

1011131323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011131323 is an equidigital number, since it uses as much as digits as its factorization.

1011131323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 1011131323 is about 31798.2911962263. The cubic root of 1011131323 is about 1003.6967581393.

Adding to 1011131323 its reverse (3231311101), we get a palindrome (4242442424).

The spelling of 1011131323 in words is "one billion, eleven million, one hundred thirty-one thousand, three hundred twenty-three".