1011131411301 has 48 divisors (see below), whose sum is σ = 1627431886080. Its totient is φ = 599682245760.

The previous prime is 1011131411263. The next prime is 1011131411351. The reversal of 1011131411301 is 1031141311101.

It is not a de Polignac number, because 1011131411301 - 2⁹ = 1011131410789 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011131411351) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 48627415 + ... + 48648203.

It is an arithmetic number, because the mean of its divisors is an integer number (33904830960).

Almost surely, 2^{1011131411301} is an apocalyptic number.

1011131411301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1011131411301 is a deficient number, since it is larger than the sum of its proper divisors (616300474779).

1011131411301 is a wasteful number, since it uses less digits than its factorization.

1011131411301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31306 (or 31303 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 1011131411301 its reverse (1031141311101), we get a palindrome (2042272722402).

The spelling of 1011131411301 in words is "one trillion, eleven billion, one hundred thirty-one million, four hundred eleven thousand, three hundred one".