10111320221 has 4 divisors (see below), whose sum is σ = 10113102012. Its totient is φ = 10109538432.

The previous prime is 10111320211. The next prime is 10111320223. The reversal of 10111320221 is 12202311101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12202311101 = 389 ⋅31368409.

It can be written as a sum of positive squares in 2 ways, for example, as 1959036121 + 8152284100 = 44261^2 + 90290^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111320221 - 2¹⁴ = 10111303837 is a prime.

It is a super-2 number, since 2×10111320221² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10111320196 and 10111320205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111320223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 882356 + ... + 893741.

It is an arithmetic number, because the mean of its divisors is an integer number (2528275503).

Almost surely, 2^10111320221 is an apocalyptic number.

It is an amenable number.

10111320221 is a deficient number, since it is larger than the sum of its proper divisors (1781791).

10111320221 is an equidigital number, since it uses as much as digits as its factorization.

10111320221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1781790.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10111320221 its reverse (12202311101), we get a palindrome (22313631322).

The spelling of 10111320221 in words is "ten billion, one hundred eleven million, three hundred twenty thousand, two hundred twenty-one".