Base | Representation |
---|---|
bin | 101111000101100111… |
… | …0001100000100101111 |
3 | 100200000020010020211102 |
4 | 1132023032030010233 |
5 | 3124043210002203 |
6 | 114242012313315 |
7 | 10206563551340 |
oct | 1361316140457 |
9 | 320006106742 |
10 | 101120000303 |
11 | 39980670993 |
12 | 17720a7283b |
13 | 96c6873a0a |
14 | 4c73ac80c7 |
15 | 296c721888 |
hex | 178b38c12f |
101120000303 has 16 divisors (see below), whose sum is σ = 117484605504. Its totient is φ = 85235708160.
The previous prime is 101120000291. The next prime is 101120000323. The reversal of 101120000303 is 303000021101.
It is a cyclic number.
It is not a de Polignac number, because 101120000303 - 232 = 96825033007 is a prime.
It is a super-2 number, since 2×1011200003032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101120000323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2291201 + ... + 2334917.
It is an arithmetic number, because the mean of its divisors is an integer number (7342787844).
Almost surely, 2101120000303 is an apocalyptic number.
101120000303 is a deficient number, since it is larger than the sum of its proper divisors (16364605201).
101120000303 is an equidigital number, since it uses as much as digits as its factorization.
101120000303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49202.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 101120000303 its reverse (303000021101), we get a palindrome (404120021404).
The spelling of 101120000303 in words is "one hundred one billion, one hundred twenty million, three hundred three", and thus it is an aban number.
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