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101120000303 = 761541743717
BaseRepresentation
bin101111000101100111…
…0001100000100101111
3100200000020010020211102
41132023032030010233
53124043210002203
6114242012313315
710206563551340
oct1361316140457
9320006106742
10101120000303
1139980670993
1217720a7283b
1396c6873a0a
144c73ac80c7
15296c721888
hex178b38c12f

101120000303 has 16 divisors (see below), whose sum is σ = 117484605504. Its totient is φ = 85235708160.

The previous prime is 101120000291. The next prime is 101120000323. The reversal of 101120000303 is 303000021101.

It is a cyclic number.

It is not a de Polignac number, because 101120000303 - 232 = 96825033007 is a prime.

It is a super-2 number, since 2×1011200003032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101120000323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2291201 + ... + 2334917.

It is an arithmetic number, because the mean of its divisors is an integer number (7342787844).

Almost surely, 2101120000303 is an apocalyptic number.

101120000303 is a deficient number, since it is larger than the sum of its proper divisors (16364605201).

101120000303 is an equidigital number, since it uses as much as digits as its factorization.

101120000303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49202.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 101120000303 its reverse (303000021101), we get a palindrome (404120021404).

The spelling of 101120000303 in words is "one hundred one billion, one hundred twenty million, three hundred three", and thus it is an aban number.

Divisors: 1 7 61 427 5417 37919 43717 306019 330437 2313059 2666737 18667159 236814989 1657704923 14445714329 101120000303