101120002100153 has 2 divisors, whose sum is σ = 101120002100154. Its totient is φ = 101120002100152.

The previous prime is 101120002100077. The next prime is 101120002100213. The reversal of 101120002100153 is 351001200021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61315978524304 + 39804023575849 = 7830452^2 + 6309043^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101120002100153 is a prime.

It is a super-3 number, since 3×101120002100153³ (a number of 43 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (101120002109153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560001050076 + 50560001050077.

It is an arithmetic number, because the mean of its divisors is an integer number (50560001050077).

Almost surely, 2^{101120002100153} is an apocalyptic number.

It is an amenable number.

101120002100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120002100153 is an equidigital number, since it uses as much as digits as its factorization.

101120002100153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 101120002100153 its reverse (351001200021101), we get a palindrome (452121202121254).

The spelling of 101120002100153 in words is "one hundred one trillion, one hundred twenty billion, two million, one hundred thousand, one hundred fifty-three".