Base | Representation |
---|---|
bin | 101111000101100111… |
… | …0001110011101100011 |
3 | 100200000020010202020122 |
4 | 1132023032032131203 |
5 | 3124043210310313 |
6 | 114242012430455 |
7 | 10206563622011 |
oct | 1361316163543 |
9 | 320006122218 |
10 | 101120010083 |
11 | 39980678274 |
12 | 17720a7842b |
13 | 96c68782c1 |
14 | 4c73acb8b1 |
15 | 296c724708 |
hex | 178b38e763 |
101120010083 has 2 divisors, whose sum is σ = 101120010084. Its totient is φ = 101120010082.
The previous prime is 101120010053. The next prime is 101120010127. The reversal of 101120010083 is 380010021101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101120010083 - 214 = 101119993699 is a prime.
It is not a weakly prime, because it can be changed into another prime (101120010053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560005041 + 50560005042.
It is an arithmetic number, because the mean of its divisors is an integer number (50560005042).
Almost surely, 2101120010083 is an apocalyptic number.
101120010083 is a deficient number, since it is larger than the sum of its proper divisors (1).
101120010083 is an equidigital number, since it uses as much as digits as its factorization.
101120010083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 101120010083 its reverse (380010021101), we get a palindrome (481130031184).
The spelling of 101120010083 in words is "one hundred one billion, one hundred twenty million, ten thousand, eighty-three".
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