Base | Representation |
---|---|
bin | 11101011011100000011… |
… | …10010101110010100011 |
3 | 10120200002021102120112002 |
4 | 32231300032111302203 |
5 | 113031414212401034 |
6 | 2052312223554215 |
7 | 133025324135003 |
oct | 16556016256243 |
9 | 3520067376462 |
10 | 1011200122019 |
11 | 35a93611a38a |
12 | 143b88a5b96b |
13 | 744817c0b89 |
14 | 36d29b2c003 |
15 | 1b484b85e7e |
hex | eb70395ca3 |
1011200122019 has 2 divisors, whose sum is σ = 1011200122020. Its totient is φ = 1011200122018.
The previous prime is 1011200122013. The next prime is 1011200122033. The reversal of 1011200122019 is 9102210021101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011200122019 is a prime.
It is a super-2 number, since 2×10112001220192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1011200122013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600061009 + 505600061010.
It is an arithmetic number, because the mean of its divisors is an integer number (505600061010).
Almost surely, 21011200122019 is an apocalyptic number.
1011200122019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011200122019 is an equidigital number, since it uses as much as digits as its factorization.
1011200122019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 20.
The spelling of 1011200122019 in words is "one trillion, eleven billion, two hundred million, one hundred twenty-two thousand, nineteen".
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