10112004013 has 4 divisors (see below), whose sum is σ = 10112359420. Its totient is φ = 10111648608.

The previous prime is 10112003999. The next prime is 10112004061. The reversal of 10112004013 is 31040021101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31040021101 = 3347 ⋅9273983.

It can be written as a sum of positive squares in 2 ways, for example, as 837928809 + 9274075204 = 28947^2 + 96302^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112004013 - 2¹³ = 10111995821 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10112003984 and 10112004002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10112004613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130920 + ... + 193297.

It is an arithmetic number, because the mean of its divisors is an integer number (2528089855).

Almost surely, 2^10112004013 is an apocalyptic number.

It is an amenable number.

10112004013 is a deficient number, since it is larger than the sum of its proper divisors (355407).

10112004013 is an equidigital number, since it uses as much as digits as its factorization.

10112004013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355406.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10112004013 its reverse (31040021101), we get a palindrome (41152025114).

The spelling of 10112004013 in words is "ten billion, one hundred twelve million, four thousand, thirteen".