Base | Representation |
---|---|
bin | 10010110101011100… |
… | …10101001100101011 |
3 | 222002201120022200111 |
4 | 21122232111030223 |
5 | 131202134420413 |
6 | 4351223515151 |
7 | 505404555343 |
oct | 113256251453 |
9 | 28081508614 |
10 | 10112029483 |
11 | 4319a82466 |
12 | 1b625b8ab7 |
13 | c51c834ca |
14 | 6bcda5d23 |
15 | 3e2b3bd3d |
hex | 25ab9532b |
10112029483 has 2 divisors, whose sum is σ = 10112029484. Its totient is φ = 10112029482.
The previous prime is 10112029451. The next prime is 10112029489. The reversal of 10112029483 is 38492021101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10112029483 - 25 = 10112029451 is a prime.
It is a super-2 number, since 2×101120294832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10112029489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056014741 + 5056014742.
It is an arithmetic number, because the mean of its divisors is an integer number (5056014742).
Almost surely, 210112029483 is an apocalyptic number.
10112029483 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112029483 is an equidigital number, since it uses as much as digits as its factorization.
10112029483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 31.
The spelling of 10112029483 in words is "ten billion, one hundred twelve million, twenty-nine thousand, four hundred eighty-three".
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