101121001121113 has 2 divisors, whose sum is σ = 101121001121114. Its totient is φ = 101121001121112.

The previous prime is 101121001120999. The next prime is 101121001121159. The reversal of 101121001121113 is 311121100121101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78750484977609 + 22370516143504 = 8874147^2 + 4729748^2 .

It is an emirp because it is prime and its reverse (311121100121101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101121001121113 is a prime.

It is a super-2 number, since 2×101121001121113² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101121001121713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560500560556 + 50560500560557.

It is an arithmetic number, because the mean of its divisors is an integer number (50560500560557).

Almost surely, 2^{101121001121113} is an apocalyptic number.

It is an amenable number.

101121001121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121001121113 is an equidigital number, since it uses as much as digits as its factorization.

101121001121113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 101121001121113 its reverse (311121100121101), we get a palindrome (412242101242214).

The spelling of 101121001121113 in words is "one hundred one trillion, one hundred twenty-one billion, one million, one hundred twenty-one thousand, one hundred thirteen".