Base | Representation |
---|---|
bin | 10010110101011101… |
… | …00110111010000111 |
3 | 222002201201000012011 |
4 | 21122232212322013 |
5 | 131202144231043 |
6 | 4351225235051 |
7 | 505405310002 |
oct | 113256467207 |
9 | 28081630164 |
10 | 10112102023 |
11 | 431a021a11 |
12 | 1b62632a87 |
13 | c51caa52a |
14 | 6bcdc4539 |
15 | 3e2b5359d |
hex | 25aba6e87 |
10112102023 has 8 divisors (see below), whose sum is σ = 10167307200. Its totient is φ = 10056926208.
The previous prime is 10112101963. The next prime is 10112102047. The reversal of 10112102023 is 32020121101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10112102023 - 217 = 10111970951 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10112101994 and 10112102012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10112100023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1339323 + ... + 1346851.
It is an arithmetic number, because the mean of its divisors is an integer number (1270913400).
Almost surely, 210112102023 is an apocalyptic number.
10112102023 is a deficient number, since it is larger than the sum of its proper divisors (55205177).
10112102023 is an equidigital number, since it uses as much as digits as its factorization.
10112102023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14681.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 10112102023 its reverse (32020121101), we get a palindrome (42132223124).
The spelling of 10112102023 in words is "ten billion, one hundred twelve million, one hundred two thousand, twenty-three".
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