1011211296817 has 2 divisors, whose sum is σ = 1011211296818. Its totient is φ = 1011211296816.

The previous prime is 1011211296773. The next prime is 1011211296863. The reversal of 1011211296817 is 7186921121101.

1011211296817 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 736714939041 + 274496357776 = 858321^2 + 523924^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011211296817 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1011211296817.

It is not a weakly prime, because it can be changed into another prime (1011211296317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505605648408 + 505605648409.

It is an arithmetic number, because the mean of its divisors is an integer number (505605648409).

Almost surely, 2^{1011211296817} is an apocalyptic number.

It is an amenable number.

1011211296817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011211296817 is an equidigital number, since it uses as much as digits as its factorization.

1011211296817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 40.

The spelling of 1011211296817 in words is "one trillion, eleven billion, two hundred eleven million, two hundred ninety-six thousand, eight hundred seventeen".