Base | Representation |
---|---|
bin | 1001001100100110100011… |
… | …1011000101001111011011 |
3 | 1022210201010120020200100212 |
4 | 2103021220323011033123 |
5 | 2311134102003130321 |
6 | 33301235110521335 |
7 | 2062401411063131 |
oct | 223115073051733 |
9 | 38721116220325 |
10 | 10112113333211 |
11 | 32495833996aa |
12 | 117396636624b |
13 | 584750431046 |
14 | 26d600c6d751 |
15 | 12808c83855b |
hex | 93268ec53db |
10112113333211 has 2 divisors, whose sum is σ = 10112113333212. Its totient is φ = 10112113333210.
The previous prime is 10112113333183. The next prime is 10112113333219. The reversal of 10112113333211 is 11233331121101.
It is a strong prime.
It is an emirp because it is prime and its reverse (11233331121101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10112113333211 - 214 = 10112113316827 is a prime.
It is not a weakly prime, because it can be changed into another prime (10112113333219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056056666605 + 5056056666606.
It is an arithmetic number, because the mean of its divisors is an integer number (5056056666606).
Almost surely, 210112113333211 is an apocalyptic number.
10112113333211 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112113333211 is an equidigital number, since it uses as much as digits as its factorization.
10112113333211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 10112113333211 its reverse (11233331121101), we get a palindrome (21345444454312).
The spelling of 10112113333211 in words is "ten trillion, one hundred twelve billion, one hundred thirteen million, three hundred thirty-three thousand, two hundred eleven".
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