1011213000213 has 12 divisors (see below), whose sum is σ = 1459976166720. Its totient is φ = 622284922896.

The previous prime is 1011213000211. The next prime is 1011213000277. The reversal of 1011213000213 is 3120003121101.

It is a happy number.

It is not a de Polignac number, because 1011213000213 - 2¹ = 1011213000211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011213000192 and 1011213000201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011213000211) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 997250973 + ... + 997251986.

It is an arithmetic number, because the mean of its divisors is an integer number (121664680560).

Almost surely, 2^{1011213000213} is an apocalyptic number.

1011213000213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1011213000213 is a deficient number, since it is larger than the sum of its proper divisors (448763166507).

1011213000213 is a wasteful number, since it uses less digits than its factorization.

1011213000213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1994502988 (or 1994502975 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1011213000213 its reverse (3120003121101), we get a palindrome (4131216121314).

The spelling of 1011213000213 in words is "one trillion, eleven billion, two hundred thirteen million, two hundred thirteen", and thus it is an aban number.