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1011221000201 is a prime number
BaseRepresentation
bin11101011011100010111…
…01111111000000001001
310120200010201201022000002
432231301131333000021
5113031440034001301
62052314251252345
7133025666452226
oct16556135770011
93520121638002
101011221000201
1135a94698a485
12143b93a4a0b5
1374485c20c29
1436d2c80494d
151b48690c16b
hexeb7177f009

1011221000201 has 2 divisors, whose sum is σ = 1011221000202. Its totient is φ = 1011221000200.

The previous prime is 1011221000197. The next prime is 1011221000213. The reversal of 1011221000201 is 1020001221101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 710352294976 + 300868705225 = 842824^2 + 548515^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011221000201 - 22 = 1011221000197 is a prime.

It is a super-2 number, since 2×10112210002012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011221002201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505610500100 + 505610500101.

It is an arithmetic number, because the mean of its divisors is an integer number (505610500101).

Almost surely, 21011221000201 is an apocalyptic number.

It is an amenable number.

1011221000201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011221000201 is an equidigital number, since it uses as much as digits as its factorization.

1011221000201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1011221000201 its reverse (1020001221101), we get a palindrome (2031222221302).

The spelling of 1011221000201 in words is "one trillion, eleven billion, two hundred twenty-one million, two hundred one", and thus it is an aban number.