Base | Representation |
---|---|
bin | 11101011011100010111… |
… | …10011010010010110011 |
3 | 10120200010201220222100022 |
4 | 32231301132122102303 |
5 | 113031440101040422 |
6 | 2052314253514055 |
7 | 133026000426152 |
oct | 16556136322263 |
9 | 3520121828308 |
10 | 1011221111987 |
11 | 35a946a56469 |
12 | 143b93aa292b |
13 | 74485c5ca88 |
14 | 36d2c833599 |
15 | 1b486930342 |
hex | eb7179a4b3 |
1011221111987 has 2 divisors, whose sum is σ = 1011221111988. Its totient is φ = 1011221111986.
The previous prime is 1011221111977. The next prime is 1011221112049. The reversal of 1011221111987 is 7891111221101.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011221111987 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011221111947) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505610555993 + 505610555994.
It is an arithmetic number, because the mean of its divisors is an integer number (505610555994).
Almost surely, 21011221111987 is an apocalyptic number.
1011221111987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011221111987 is an equidigital number, since it uses as much as digits as its factorization.
1011221111987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 35.
The spelling of 1011221111987 in words is "one trillion, eleven billion, two hundred twenty-one million, one hundred eleven thousand, nine hundred eighty-seven".
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