Base | Representation |
---|---|
bin | 11101011011100010111… |
… | …10110100101101101011 |
3 | 10120200010202010110210022 |
4 | 32231301132310231223 |
5 | 113031440113021303 |
6 | 2052314300111055 |
7 | 133026001356515 |
oct | 16556136645553 |
9 | 3520122113708 |
10 | 1011221220203 |
11 | 35a94701a7a7 |
12 | 143b93b3548b |
13 | 74485c9a0cc |
14 | 36d2c860bb5 |
15 | 1b486952438 |
hex | eb717b4b6b |
1011221220203 has 4 divisors (see below), whose sum is σ = 1011223241280. Its totient is φ = 1011219199128.
The previous prime is 1011221220169. The next prime is 1011221220227. The reversal of 1011221220203 is 3020221221101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1011221220203 - 214 = 1011221203819 is a prime.
It is a super-2 number, since 2×10112212202032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1011221220293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355526 + ... + 1465892.
It is an arithmetic number, because the mean of its divisors is an integer number (252805810320).
Almost surely, 21011221220203 is an apocalyptic number.
1011221220203 is a deficient number, since it is larger than the sum of its proper divisors (2021077).
1011221220203 is an equidigital number, since it uses as much as digits as its factorization.
1011221220203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2021076.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1011221220203 its reverse (3020221221101), we get a palindrome (4031442441304).
The spelling of 1011221220203 in words is "one trillion, eleven billion, two hundred twenty-one million, two hundred twenty thousand, two hundred three".
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