Base | Representation |
---|---|
bin | 11101011011100010111… |
… | …10110100101110000011 |
3 | 10120200010202010110211012 |
4 | 32231301132310232003 |
5 | 113031440113021402 |
6 | 2052314300111135 |
7 | 133026001356551 |
oct | 16556136645603 |
9 | 3520122113735 |
10 | 1011221220227 |
11 | 35a94701a819 |
12 | 143b93b354ab |
13 | 74485c9a11a |
14 | 36d2c860bd1 |
15 | 1b486952452 |
hex | eb717b4b83 |
1011221220227 has 2 divisors, whose sum is σ = 1011221220228. Its totient is φ = 1011221220226.
The previous prime is 1011221220169. The next prime is 1011221220271. The reversal of 1011221220227 is 7220221221101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011221220227 - 28 = 1011221219971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011221220727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505610610113 + 505610610114.
It is an arithmetic number, because the mean of its divisors is an integer number (505610610114).
Almost surely, 21011221220227 is an apocalyptic number.
1011221220227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011221220227 is an equidigital number, since it uses as much as digits as its factorization.
1011221220227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 1011221220227 its reverse (7220221221101), we get a palindrome (8231442441328).
The spelling of 1011221220227 in words is "one trillion, eleven billion, two hundred twenty-one million, two hundred twenty thousand, two hundred twenty-seven".
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