Base | Representation |
---|---|
bin | 11101011011100011011… |
… | …10001011001100001111 |
3 | 10120200011000200220222210 |
4 | 32231301232023030033 |
5 | 113031442130310211 |
6 | 2052314522241503 |
7 | 133026050520123 |
oct | 16556156131417 |
9 | 3520130626883 |
10 | 1011225244431 |
11 | 35a949319206 |
12 | 143b95356293 |
13 | 74486a789cc |
14 | 36d2d1cb583 |
15 | 1b486e999a6 |
hex | eb71b8b30f |
1011225244431 has 4 divisors (see below), whose sum is σ = 1348300325912. Its totient is φ = 674150162952.
The previous prime is 1011225244417. The next prime is 1011225244439. The reversal of 1011225244431 is 1344425221101.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1011225244431 - 25 = 1011225244399 is a prime.
It is a super-2 number, since 2×10112252444312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1011225244439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168537540736 + ... + 168537540741.
It is an arithmetic number, because the mean of its divisors is an integer number (337075081478).
Almost surely, 21011225244431 is an apocalyptic number.
1011225244431 is a deficient number, since it is larger than the sum of its proper divisors (337075081481).
1011225244431 is an equidigital number, since it uses as much as digits as its factorization.
1011225244431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 337075081480.
The product of its (nonzero) digits is 7680, while the sum is 30.
The spelling of 1011225244431 in words is "one trillion, eleven billion, two hundred twenty-five million, two hundred forty-four thousand, four hundred thirty-one".
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