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101123120017 is a prime number
BaseRepresentation
bin101111000101101101…
…0000101101110010001
3100200000102222202021101
41132023122011232101
53124100004320032
6114242203224401
710206632223613
oct1361332055621
9320012882241
10101123120017
1139982401867
1217721b18101
1396c73c69ba
144c7429adb3
15296cb3ade7
hex178b685b91

101123120017 has 2 divisors, whose sum is σ = 101123120018. Its totient is φ = 101123120016.

The previous prime is 101123120009. The next prime is 101123120027. The reversal of 101123120017 is 710021321101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96746503681 + 4376616336 = 311041^2 + 66156^2 .

It is an emirp because it is prime and its reverse (710021321101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101123120017 - 23 = 101123120009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101123119976 and 101123120003.

It is not a weakly prime, because it can be changed into another prime (101123120027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561560008 + 50561560009.

It is an arithmetic number, because the mean of its divisors is an integer number (50561560009).

Almost surely, 2101123120017 is an apocalyptic number.

It is an amenable number.

101123120017 is a deficient number, since it is larger than the sum of its proper divisors (1).

101123120017 is an equidigital number, since it uses as much as digits as its factorization.

101123120017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 101123120017 its reverse (710021321101), we get a palindrome (811144441118).

The spelling of 101123120017 in words is "one hundred one billion, one hundred twenty-three million, one hundred twenty thousand, seventeen".