101123123131 has 2 divisors, whose sum is σ = 101123123132. Its totient is φ = 101123123130.

The previous prime is 101123123093. The next prime is 101123123149. The reversal of 101123123131 is 131321321101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101123123131 - 2²⁹ = 100586252219 is a prime.

It is a super-2 number, since 2×101123123131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101123123099 and 101123123108.

It is not a weakly prime, because it can be changed into another prime (101123123191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561561565 + 50561561566.

It is an arithmetic number, because the mean of its divisors is an integer number (50561561566).

Almost surely, 2^101123123131 is an apocalyptic number.

101123123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101123123131 is an equidigital number, since it uses as much as digits as its factorization.

101123123131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 101123123131 its reverse (131321321101), we get a palindrome (232444444232).

The spelling of 101123123131 in words is "one hundred one billion, one hundred twenty-three million, one hundred twenty-three thousand, one hundred thirty-one".