1011234113 has 2 divisors, whose sum is σ = 1011234114. Its totient is φ = 1011234112.

The previous prime is 1011234097. The next prime is 1011234143. The reversal of 1011234113 is 3114321101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975437824 + 35796289 = 31232^2 + 5983^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011234113 - 2⁴ = 1011234097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011234091 and 1011234100.

It is not a weakly prime, because it can be changed into another prime (1011234143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505617056 + 505617057.

It is an arithmetic number, because the mean of its divisors is an integer number (505617057).

Almost surely, 2^1011234113 is an apocalyptic number.

It is an amenable number.

1011234113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011234113 is an equidigital number, since it uses as much as digits as its factorization.

1011234113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1011234113 is about 31799.9074369722. The cubic root of 1011234113 is about 1003.7307683915.

Adding to 1011234113 its reverse (3114321101), we get a palindrome (4125555214).

The spelling of 1011234113 in words is "one billion, eleven million, two hundred thirty-four thousand, one hundred thirteen".