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101124139937 is a prime number
BaseRepresentation
bin101111000101101110…
…1111110101110100001
3100200000111220120100012
41132023131332232201
53124100234434222
6114242241134305
710206644002262
oct1361335765641
9320014816305
10101124139937
1139982a39077
121772232a395
1396c7692cc2
144c74484969
15296cc8d1e2
hex178b77eba1

101124139937 has 2 divisors, whose sum is σ = 101124139938. Its totient is φ = 101124139936.

The previous prime is 101124139933. The next prime is 101124140069. The reversal of 101124139937 is 739931421101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66414959521 + 34709180416 = 257711^2 + 186304^2 .

It is a cyclic number.

It is not a de Polignac number, because 101124139937 - 22 = 101124139933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101124139894 and 101124139903.

It is not a weakly prime, because it can be changed into another prime (101124139933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50562069968 + 50562069969.

It is an arithmetic number, because the mean of its divisors is an integer number (50562069969).

Almost surely, 2101124139937 is an apocalyptic number.

It is an amenable number.

101124139937 is a deficient number, since it is larger than the sum of its proper divisors (1).

101124139937 is an equidigital number, since it uses as much as digits as its factorization.

101124139937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 101124139937 in words is "one hundred one billion, one hundred twenty-four million, one hundred thirty-nine thousand, nine hundred thirty-seven".