Base | Representation |
---|---|
bin | 11101011011100101101… |
… | …10110111011100010011 |
3 | 10120200012100120001101111 |
4 | 32231302312313130103 |
5 | 113032012020100201 |
6 | 2052320442514151 |
7 | 133026401503636 |
oct | 16556266673423 |
9 | 3520170501344 |
10 | 1011244300051 |
11 | 35a959053a57 |
12 | 143b9b805957 |
13 | 7448a9bb31b |
14 | 36d3194bc1d |
15 | 1b4889b0b51 |
hex | eb72db7713 |
1011244300051 has 2 divisors, whose sum is σ = 1011244300052. Its totient is φ = 1011244300050.
The previous prime is 1011244300019. The next prime is 1011244300067. The reversal of 1011244300051 is 1500034421101.
It is a strong prime.
It is an emirp because it is prime and its reverse (1500034421101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1011244300051 - 25 = 1011244300019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011244299995 and 1011244300031.
It is not a weakly prime, because it can be changed into another prime (1011244300081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505622150025 + 505622150026.
It is an arithmetic number, because the mean of its divisors is an integer number (505622150026).
Almost surely, 21011244300051 is an apocalyptic number.
1011244300051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011244300051 is an equidigital number, since it uses as much as digits as its factorization.
1011244300051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 1011244300051 its reverse (1500034421101), we get a palindrome (2511278721152).
The spelling of 1011244300051 in words is "one trillion, eleven billion, two hundred forty-four million, three hundred thousand, fifty-one".
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