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1011252310433 is a prime number
BaseRepresentation
bin11101011011100110101…
…01011011000110100001
310120200012220122000120022
432231303111123012201
5113032021042413213
62052321330323225
7133026526545551
oct16556325330641
93520186560508
101011252310433
1135a962625302
12143ba2429515
137448c5643b1
1436d32a35161
151b489544308
hexeb7355b1a1

1011252310433 has 2 divisors, whose sum is σ = 1011252310434. Its totient is φ = 1011252310432.

The previous prime is 1011252310399. The next prime is 1011252310507. The reversal of 1011252310433 is 3340132521101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 761235310144 + 250017000289 = 872488^2 + 500017^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011252310433 - 228 = 1010983874977 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011252313433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505626155216 + 505626155217.

It is an arithmetic number, because the mean of its divisors is an integer number (505626155217).

Almost surely, 21011252310433 is an apocalyptic number.

It is an amenable number.

1011252310433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011252310433 is an equidigital number, since it uses as much as digits as its factorization.

1011252310433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 1011252310433 its reverse (3340132521101), we get a palindrome (4351384831534).

The spelling of 1011252310433 in words is "one trillion, eleven billion, two hundred fifty-two million, three hundred ten thousand, four hundred thirty-three".