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101130001057 is a prime number
BaseRepresentation
bin101111000101111010…
…0010101101010100001
3100200000220221100021201
41132023310111222201
53124103240013212
6114243010521201
710210044553141
oct1361364255241
9320026840251
10101130001057
1139986281678
1217724296201
1396c8965a17
144c7516c921
15296d549b57
hex178bd15aa1

101130001057 has 2 divisors, whose sum is σ = 101130001058. Its totient is φ = 101130001056.

The previous prime is 101130000931. The next prime is 101130001061. The reversal of 101130001057 is 750100031101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83708376976 + 17421624081 = 289324^2 + 131991^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101130001057 is a prime.

It is a super-2 number, since 2×1011300010572 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101130001657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565000528 + 50565000529.

It is an arithmetic number, because the mean of its divisors is an integer number (50565000529).

Almost surely, 2101130001057 is an apocalyptic number.

It is an amenable number.

101130001057 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130001057 is an equidigital number, since it uses as much as digits as its factorization.

101130001057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 105, while the sum is 19.

Adding to 101130001057 its reverse (750100031101), we get a palindrome (851230032158).

The spelling of 101130001057 in words is "one hundred one billion, one hundred thirty million, one thousand, fifty-seven".