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101130011033100 = 223527433068936493
BaseRepresentation
bin10110111111101000101010…
…011000100011111000001100
3111021001221020100102201221220
4112333220222120203320030
5101223403230311024400
6555030252524523340
730205254643350150
oct2677505230437014
9437057210381856
10101130011033100
112a24aaa6857565
12b4138100b0550
13445769967a16a
141ad8a0bd97060
15ba5954d287a0
hex5bfa2a623e0c

101130011033100 has 288 divisors, whose sum is σ = 342200582760960. Its totient is φ = 22576508559360.

The previous prime is 101130011033087. The next prime is 101130011033147. The reversal of 101130011033100 is 1330110031101.

101130011033100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1011300110331002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 101130011033100.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2771198454 + ... + 2771234946.

It is an arithmetic number, because the mean of its divisors is an integer number (1188196467920).

Almost surely, 2101130011033100 is an apocalyptic number.

101130011033100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101130011033100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (171100291380480).

101130011033100 is an abundant number, since it is smaller than the sum of its proper divisors (241070571727860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101130011033100 is a wasteful number, since it uses less digits than its factorization.

101130011033100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67249 (or 67242 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 101130011033100 its reverse (1330110031101), we get a palindrome (102460121064201).

The spelling of 101130011033100 in words is "one hundred one trillion, one hundred thirty billion, eleven million, thirty-three thousand, one hundred".