101130011033101 has 4 divisors (see below), whose sum is σ = 101331064733472. Its totient is φ = 100928957332732.

The previous prime is 101130011033087. The next prime is 101130011033147. The reversal of 101130011033101 is 101330110031101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101130011033101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101130011033201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100526849431 + ... + 100526850436.

It is an arithmetic number, because the mean of its divisors is an integer number (25332766183368).

Almost surely, 2^{101130011033101} is an apocalyptic number.

It is an amenable number.

101130011033101 is a deficient number, since it is larger than the sum of its proper divisors (201053700371).

101130011033101 is an equidigital number, since it uses as much as digits as its factorization.

101130011033101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201053700370.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 101130011033101 its reverse (101330110031101), we get a palindrome (202460121064202).

The spelling of 101130011033101 in words is "one hundred one trillion, one hundred thirty billion, eleven million, thirty-three thousand, one hundred one".