1011300122000 has 240 divisors, whose sum is σ = 2942656769520. Its totient is φ = 334774272000.

The previous prime is 1011300121999. The next prime is 1011300122023. The reversal of 1011300122000 is 2210031101.

It can be written as a sum of positive squares in 8 ways, for example, as 58349301136 + 952950820864 = 241556^2 + 976192^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2664080 + ... + 3019920.

It is an arithmetic number, because the mean of its divisors is an integer number (12261069873).

Almost surely, 2^{1011300122000} is an apocalyptic number.

1011300122000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011300122000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1471328384760).

1011300122000 is an abundant number, since it is smaller than the sum of its proper divisors (1931356647520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011300122000 is a wasteful number, since it uses less digits than its factorization.

1011300122000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355907 (or 355884 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 1011300122000 its reverse (2210031101), we get a palindrome (1013510153101).

The spelling of 1011300122000 in words is "one trillion, eleven billion, three hundred million, one hundred twenty-two thousand".