1011300130414 has 8 divisors (see below), whose sum is σ = 1733657366448. Its totient is φ = 433414341600.

The previous prime is 1011300130403. The next prime is 1011300130429. The reversal of 1011300130414 is 4140310031101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1011300130414² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011300130391 and 1011300130400.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36117861787 + ... + 36117861814.

It is an arithmetic number, because the mean of its divisors is an integer number (216707170806).

Almost surely, 2^{1011300130414} is an apocalyptic number.

1011300130414 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1011300130414 is a deficient number, since it is larger than the sum of its proper divisors (722357236034).

1011300130414 is an equidigital number, since it uses as much as digits as its factorization.

1011300130414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72235723610.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1011300130414 its reverse (4140310031101), we get a palindrome (5151610161515).

The spelling of 1011300130414 in words is "one trillion, eleven billion, three hundred million, one hundred thirty thousand, four hundred fourteen".