Base | Representation |
---|---|
bin | 10110111111101000101011… |
… | …101101100101110001110010 |
3 | 111021001221021220101012010021 |
4 | 112333220223231211301302 |
5 | 101223403302012314442 |
6 | 555030255042354054 |
7 | 30205255333664506 |
oct | 2677505355456162 |
9 | 437057256335107 |
10 | 101130033323122 |
11 | 2a2500083a1371 |
12 | b41381765b92a |
13 | 44576a1182a1b |
14 | 1ad8a10d1a306 |
15 | ba5956c7ce67 |
hex | 5bfa2bb65c72 |
101130033323122 has 4 divisors (see below), whose sum is σ = 151695049984686. Its totient is φ = 50565016661560.
The previous prime is 101130033323119. The next prime is 101130033323141. The reversal of 101130033323122 is 221323330031101.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 53575065611001 + 47554967712121 = 7319499^2 + 6896011^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25282508330779 + ... + 25282508330782.
Almost surely, 2101130033323122 is an apocalyptic number.
101130033323122 is a deficient number, since it is larger than the sum of its proper divisors (50565016661564).
101130033323122 is an equidigital number, since it uses as much as digits as its factorization.
101130033323122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50565016661563.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 101130033323122 its reverse (221323330031101), we get a palindrome (322453363354223).
The spelling of 101130033323122 in words is "one hundred one trillion, one hundred thirty billion, thirty-three million, three hundred twenty-three thousand, one hundred twenty-two".
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