Base | Representation |
---|---|
bin | 10010110101100100… |
… | …00100110100101011 |
3 | 222002210102012001111 |
4 | 21122302010310223 |
5 | 131202412322422 |
6 | 4351300531151 |
7 | 505416114022 |
oct | 113262046453 |
9 | 28083365044 |
10 | 10113010987 |
11 | 431a592922 |
12 | 1b629b0ab7 |
13 | c52238191 |
14 | 6bd17d8b9 |
15 | 3e2c82a77 |
hex | 25ac84d2b |
10113010987 has 2 divisors, whose sum is σ = 10113010988. Its totient is φ = 10113010986.
The previous prime is 10113010969. The next prime is 10113011047. The reversal of 10113010987 is 78901031101.
10113010987 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10113010987 - 215 = 10112978219 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113010387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056505493 + 5056505494.
It is an arithmetic number, because the mean of its divisors is an integer number (5056505494).
Almost surely, 210113010987 is an apocalyptic number.
10113010987 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113010987 is an equidigital number, since it uses as much as digits as its factorization.
10113010987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 31.
The spelling of 10113010987 in words is "ten billion, one hundred thirteen million, ten thousand, nine hundred eighty-seven".
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