10113012100099 has 2 divisors, whose sum is σ = 10113012100100. Its totient is φ = 10113012100098.

The previous prime is 10113012100063. The next prime is 10113012100171. The reversal of 10113012100099 is 99000121031101.

10113012100099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113012100099 - 2¹¹ = 10113012098051 is a prime.

It is not a weakly prime, because it can be changed into another prime (10113012100799) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056506050049 + 5056506050050.

It is an arithmetic number, because the mean of its divisors is an integer number (5056506050050).

Almost surely, 2^{10113012100099} is an apocalyptic number.

10113012100099 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113012100099 is an equidigital number, since it uses as much as digits as its factorization.

10113012100099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 28.

The spelling of 10113012100099 in words is "ten trillion, one hundred thirteen billion, twelve million, one hundred thousand, ninety-nine".