Base | Representation |
---|---|
bin | 1001001100101001111010… |
… | …0000001010001100111111 |
3 | 1022210210110012201010221121 |
4 | 2103022132200022030333 |
5 | 2311142422113322221 |
6 | 33301504221411411 |
7 | 2062432604521123 |
oct | 223123640121477 |
9 | 38723405633847 |
10 | 10113012245311 |
11 | 32499a4848668 |
12 | 1173b77409b67 |
13 | 5848647364b1 |
14 | 26d6883c5583 |
15 | 1280e16eca41 |
hex | 9329e80a33f |
10113012245311 has 4 divisors (see below), whose sum is σ = 10113060160872. Its totient is φ = 10112964329752.
The previous prime is 10113012245269. The next prime is 10113012245321. The reversal of 10113012245311 is 11354221031101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10113012245311 - 221 = 10113010148159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10113012245321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23639785 + ... + 24063778.
It is an arithmetic number, because the mean of its divisors is an integer number (2528265040218).
Almost surely, 210113012245311 is an apocalyptic number.
10113012245311 is a deficient number, since it is larger than the sum of its proper divisors (47915561).
10113012245311 is an equidigital number, since it uses as much as digits as its factorization.
10113012245311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47915560.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 10113012245311 its reverse (11354221031101), we get a palindrome (21467233276412).
The spelling of 10113012245311 in words is "ten trillion, one hundred thirteen billion, twelve million, two hundred forty-five thousand, three hundred eleven".
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