Search a number
-
+
1011302313097 is a prime number
BaseRepresentation
bin11101011011101100101…
…00001010110010001001
310120200100101201102022211
432231312110022302021
5113032121343004342
62052330314145121
7133031004554116
oct16556624126211
93520311642284
101011302313097
1135a98887801a
12143bb71221a1
1374499a20a7b
1436d3952d90d
151b48db1ec17
hexeb7650ac89

1011302313097 has 2 divisors, whose sum is σ = 1011302313098. Its totient is φ = 1011302313096.

The previous prime is 1011302313083. The next prime is 1011302313139. The reversal of 1011302313097 is 7903132031101.

1011302313097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 972819251856 + 38483061241 = 986316^2 + 196171^2 .

It is an emirp because it is prime and its reverse (7903132031101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011302313097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011302313067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505651156548 + 505651156549.

It is an arithmetic number, because the mean of its divisors is an integer number (505651156549).

Almost surely, 21011302313097 is an apocalyptic number.

It is an amenable number.

1011302313097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011302313097 is an equidigital number, since it uses as much as digits as its factorization.

1011302313097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 31.

Adding to 1011302313097 its reverse (7903132031101), we get a palindrome (8914434344198).

The spelling of 1011302313097 in words is "one trillion, eleven billion, three hundred two million, three hundred thirteen thousand, ninety-seven".