Base | Representation |
---|---|
bin | 101111000101111010… |
… | …1010001000000001111 |
3 | 100200000221101200200201 |
4 | 1132023311101000033 |
5 | 3124103320302421 |
6 | 114243020034331 |
7 | 10210046614561 |
oct | 1361365210017 |
9 | 320027350621 |
10 | 101130244111 |
11 | 39986428246 |
12 | 177243929a7 |
13 | 96c8a1c540 |
14 | 4c751d3331 |
15 | 296d596b91 |
hex | 178bd5100f |
101130244111 has 4 divisors (see below), whose sum is σ = 108909493672. Its totient is φ = 93350994552.
The previous prime is 101130244099. The next prime is 101130244133. The reversal of 101130244111 is 111442031101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111442031101 = 103 ⋅1081961467.
It is a cyclic number.
It is not a de Polignac number, because 101130244111 - 223 = 101121855503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101130244141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3889624761 + ... + 3889624786.
It is an arithmetic number, because the mean of its divisors is an integer number (27227373418).
Almost surely, 2101130244111 is an apocalyptic number.
101130244111 is a deficient number, since it is larger than the sum of its proper divisors (7779249561).
101130244111 is an equidigital number, since it uses as much as digits as its factorization.
101130244111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7779249560.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 101130244111 its reverse (111442031101), we get a palindrome (212572275212).
The spelling of 101130244111 in words is "one hundred one billion, one hundred thirty million, two hundred forty-four thousand, one hundred eleven".
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