101131001320200 has 384 divisors, whose sum is σ = 346432939372800. Its totient is φ = 24274637291520.

The previous prime is 101131001320169. The next prime is 101131001320231. The reversal of 101131001320200 is 2023100131101.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (101131001320169) and next prime (101131001320231).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 101131001320200.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1734368646 + ... + 1734426954.

It is an arithmetic number, because the mean of its divisors is an integer number (902169112950).

Almost surely, 2^{101131001320200} is an apocalyptic number.

101131001320200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101131001320200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173216469686400).

101131001320200 is an abundant number, since it is smaller than the sum of its proper divisors (245301938052600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101131001320200 is a wasteful number, since it uses less digits than its factorization.

101131001320200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65761 (or 65752 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 101131001320200 its reverse (2023100131101), we get a palindrome (103154101451301).

The spelling of 101131001320200 in words is "one hundred one trillion, one hundred thirty-one billion, one million, three hundred twenty thousand, two hundred".