Base | Representation |
---|---|
bin | 101111000101111110… |
… | …0011011000010001011 |
3 | 100200001001221000012121 |
4 | 1132023330123002023 |
5 | 3124104310321303 |
6 | 114243124152111 |
7 | 10210101560332 |
oct | 1361374330213 |
9 | 320031830177 |
10 | 101132120203 |
11 | 39987499834 |
12 | 17724b38637 |
13 | 96c922845a |
14 | 4c75560d19 |
15 | 296d8179bd |
hex | 178bf1b08b |
101132120203 has 2 divisors, whose sum is σ = 101132120204. Its totient is φ = 101132120202.
The previous prime is 101132120197. The next prime is 101132120207. The reversal of 101132120203 is 302021231101.
It is a strong prime.
It is an emirp because it is prime and its reverse (302021231101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101132120203 - 25 = 101132120171 is a prime.
It is a super-2 number, since 2×1011321202032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101132120207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566060101 + 50566060102.
It is an arithmetic number, because the mean of its divisors is an integer number (50566060102).
Almost surely, 2101132120203 is an apocalyptic number.
101132120203 is a deficient number, since it is larger than the sum of its proper divisors (1).
101132120203 is an equidigital number, since it uses as much as digits as its factorization.
101132120203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 101132120203 its reverse (302021231101), we get a palindrome (403153351304).
The spelling of 101132120203 in words is "one hundred one billion, one hundred thirty-two million, one hundred twenty thousand, two hundred three".
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