101132121101113 has 2 divisors, whose sum is σ = 101132121101114. Its totient is φ = 101132121101112.

The previous prime is 101132121101047. The next prime is 101132121101171. The reversal of 101132121101113 is 311101121231101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94799665926144 + 6332455174969 = 9736512^2 + 2516437^2 .

It is a cyclic number.

It is not a de Polignac number, because 101132121101113 - 2¹³ = 101132121092921 is a prime.

It is not a weakly prime, because it can be changed into another prime (101132121101183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566060550556 + 50566060550557.

It is an arithmetic number, because the mean of its divisors is an integer number (50566060550557).

Almost surely, 2^{101132121101113} is an apocalyptic number.

It is an amenable number.

101132121101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101132121101113 is an equidigital number, since it uses as much as digits as its factorization.

101132121101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 19.

Adding to 101132121101113 its reverse (311101121231101), we get a palindrome (412233242332214).

The spelling of 101132121101113 in words is "one hundred one trillion, one hundred thirty-two billion, one hundred twenty-one million, one hundred one thousand, one hundred thirteen".