1011321313021 has 4 divisors (see below), whose sum is σ = 1012061125152. Its totient is φ = 1010581500892.

The previous prime is 1011321313019. The next prime is 1011321313073. The reversal of 1011321313021 is 1203131231101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011321313021 - 2¹ = 1011321313019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011321313021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011321313001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369904015 + ... + 369906748.

It is an arithmetic number, because the mean of its divisors is an integer number (253015281288).

Almost surely, 2^{1011321313021} is an apocalyptic number.

It is an amenable number.

1011321313021 is a deficient number, since it is larger than the sum of its proper divisors (739812131).

1011321313021 is an equidigital number, since it uses as much as digits as its factorization.

1011321313021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739812130.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1011321313021 its reverse (1203131231101), we get a palindrome (2214452544122).

The spelling of 1011321313021 in words is "one trillion, eleven billion, three hundred twenty-one million, three hundred thirteen thousand, twenty-one".