1011321313020 has 144 divisors (see below), whose sum is σ = 3152585899008. Its totient is φ = 262230220800.

The previous prime is 1011321313019. The next prime is 1011321313073. The reversal of 1011321313020 is 203131231101.

1011321313020 is a `hidden beast` number, since 1 + 0 + 11 + 321 + 31 + 302 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1011321312984 and 1011321313002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10615237 + ... + 10710083.

It is an arithmetic number, because the mean of its divisors is an integer number (21892957632).

Almost surely, 2^{1011321313020} is an apocalyptic number.

1011321313020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011321313020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1576292949504).

1011321313020 is an abundant number, since it is smaller than the sum of its proper divisors (2141264585988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011321313020 is a wasteful number, since it uses less digits than its factorization.

1011321313020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96500 (or 96495 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1011321313020 its reverse (203131231101), we get a palindrome (1214452544121).

The spelling of 1011321313020 in words is "one trillion, eleven billion, three hundred twenty-one million, three hundred thirteen thousand, twenty".