Base | Representation |
---|---|
bin | 11101011011101110111… |
… | …11110110100010101100 |
3 | 10120200101210001101201221 |
4 | 32231313133312202230 |
5 | 113032141432400012 |
6 | 2052332303313124 |
7 | 133031335315564 |
oct | 16556737664254 |
9 | 3520353041657 |
10 | 1011322153132 |
11 | 35a998a99145 |
12 | 1440018ab7a4 |
13 | 744a0b79435 |
14 | 36d3c015da4 |
15 | 1b49073d507 |
hex | eb777f68ac |
1011322153132 has 6 divisors (see below), whose sum is σ = 1769813767988. Its totient is φ = 505661076564.
The previous prime is 1011322153129. The next prime is 1011322153141. The reversal of 1011322153132 is 2313512231101.
It is a junction number, because it is equal to n+sod(n) for n = 1011322153097 and 1011322153106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126415269138 + ... + 126415269145.
Almost surely, 21011322153132 is an apocalyptic number.
It is an amenable number.
1011322153132 is a deficient number, since it is larger than the sum of its proper divisors (758491614856).
1011322153132 is a wasteful number, since it uses less digits than its factorization.
1011322153132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252830538287 (or 252830538285 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1011322153132 its reverse (2313512231101), we get a palindrome (3324834384233).
The spelling of 1011322153132 in words is "one trillion, eleven billion, three hundred twenty-two million, one hundred fifty-three thousand, one hundred thirty-two".
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