Base | Representation |
---|---|
bin | 10110111111101011100011… |
… | …001011010000111000000001 |
3 | 111021002020020102012021000011 |
4 | 112333223203023100320001 |
5 | 101223431103000113403 |
6 | 555031524315024521 |
7 | 30205424530432402 |
oct | 2677534313207001 |
9 | 437066212167004 |
10 | 101133111332353 |
11 | 2a2513478a3251 |
12 | b41433643b141 |
13 | 4457a71a7b469 |
14 | 1ad8c23a2b9a9 |
15 | ba5a870d0a6d |
hex | 5bfae32d0e01 |
101133111332353 has 2 divisors, whose sum is σ = 101133111332354. Its totient is φ = 101133111332352.
The previous prime is 101133111332329. The next prime is 101133111332417. The reversal of 101133111332353 is 353233111331101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72514217118784 + 28618894213569 = 8515528^2 + 5349663^2 .
It is a cyclic number.
It is not a de Polignac number, because 101133111332353 - 221 = 101133109235201 is a prime.
It is not a weakly prime, because it can be changed into another prime (101133111335353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566555666176 + 50566555666177.
It is an arithmetic number, because the mean of its divisors is an integer number (50566555666177).
Almost surely, 2101133111332353 is an apocalyptic number.
It is an amenable number.
101133111332353 is a deficient number, since it is larger than the sum of its proper divisors (1).
101133111332353 is an equidigital number, since it uses as much as digits as its factorization.
101133111332353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 31.
Adding to 101133111332353 its reverse (353233111331101), we get a palindrome (454366222663454).
The spelling of 101133111332353 in words is "one hundred one trillion, one hundred thirty-three billion, one hundred eleven million, three hundred thirty-two thousand, three hundred fifty-three".
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