1011331214 has 4 divisors (see below), whose sum is σ = 1516996824. Its totient is φ = 505665606.

The previous prime is 1011331199. The next prime is 1011331283. The reversal of 1011331214 is 4121331101.

1011331214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1011331192 and 1011331201.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252832802 + ... + 252832805.

It is an arithmetic number, because the mean of its divisors is an integer number (379249206).

Almost surely, 2^1011331214 is an apocalyptic number.

1011331214 is a deficient number, since it is larger than the sum of its proper divisors (505665610).

1011331214 is an equidigital number, since it uses as much as digits as its factorization.

1011331214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 505665609.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1011331214 is about 31801.4341500505. The cubic root of 1011331214 is about 1003.7628942005.

Adding to 1011331214 its reverse (4121331101), we get a palindrome (5132662315).

The spelling of 1011331214 in words is "one billion, eleven million, three hundred thirty-one thousand, two hundred fourteen".