Base | Representation |
---|---|
bin | 10010110101100110… |
… | …10011011100001001 |
3 | 222002211000112202221 |
4 | 21122303103130021 |
5 | 131203003124001 |
6 | 4351311454041 |
7 | 505421624602 |
oct | 113263233411 |
9 | 28084015687 |
10 | 10113333001 |
11 | 431a792852 |
12 | 1b62b27321 |
13 | c5231b915 |
14 | 6bd224da9 |
15 | 3e2ce81a1 |
hex | 25acd3709 |
10113333001 has 2 divisors, whose sum is σ = 10113333002. Its totient is φ = 10113333000.
The previous prime is 10113332989. The next prime is 10113333037. The reversal of 10113333001 is 10033331101.
10113333001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9312443001 + 800890000 = 96501^2 + 28300^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113333001 - 25 = 10113332969 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113333301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056666500 + 5056666501.
It is an arithmetic number, because the mean of its divisors is an integer number (5056666501).
Almost surely, 210113333001 is an apocalyptic number.
It is an amenable number.
10113333001 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113333001 is an equidigital number, since it uses as much as digits as its factorization.
10113333001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 10113333001 its reverse (10033331101), we get a palindrome (20146664102).
The spelling of 10113333001 in words is "ten billion, one hundred thirteen million, three hundred thirty-three thousand, one".
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